>// If `reference` is pattern matched against `&val`, it results
>// in a comparison like:
>// `&i32`
>// `&val`
>// ^ We see that if the matching `&`s are dropped, then the `i32`
>// should be assigned to `val`.
>&val => println!("Got a value via destructuring: {:?}", val),
>}
>// To avoid the `&`, you dereference before matching.
>match *reference {
>val => println!("Got a value via dereferencing: {:?}", val),
>}
>// What if you don't start with a reference? `reference` was a `&`
>// because the right side was already a reference. This is not
>// a reference because the right side is not one.
>let _not_a_reference = 3;
>// Rust provides `ref` for exactly this purpose. It modifies the
>// assignment so that a reference is created for the element; this
>// reference is assigned.
>let ref _is_a_reference = 3;
>// Accordingly, by defining 2 values without references, references
>// can be retrieved via `ref` and `ref mut`.
>let value = 5;
>let mut mut_value = 6;
>// Use `ref` keyword to create a reference.
>match value {
>ref r => println!("Got a reference to a value: {:?}", r),
>}
>// Use `ref mut` similarly.
>match mut_value {
>ref mut m => {
>// Got a reference. Gotta dereference it before we can
>// add anything to it.
>*m += 10;
>println!("We added 10. `mut_value`: {:?}", m);
>},
>}
>}
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